4.9x^2+25x-5000=0

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Solution for 4.9x^2+25x-5000=0 equation:



4.9x^2+25x-5000=0
a = 4.9; b = 25; c = -5000;
Δ = b2-4ac
Δ = 252-4·4.9·(-5000)
Δ = 98625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{98625}=\sqrt{25*3945}=\sqrt{25}*\sqrt{3945}=5\sqrt{3945}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{3945}}{2*4.9}=\frac{-25-5\sqrt{3945}}{9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{3945}}{2*4.9}=\frac{-25+5\sqrt{3945}}{9.8} $

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